Java Program to check for Disarium Number

Write a Program in Java to input a number and check whether it is a Disarium Number or not.

Note: A number will be called DISARIUM if sum of its digits powered with their respective position is equal to the original number.

For example 135 is a DISARIUM
(Workings 1¹+3²+5³ = 135, some other DISARIUM are 89, 175, 518 etc)

import java.io.*;

class Disarium

    {

    public static void main(String[] args)throws IOException

        {

            BufferedReader br=new BufferedReader (new InputStreamReader(System.in));

            System.out.print("Enter a number : ");

            int n = Integer.parseInt(br.readLine());

            int copy = n, d = 0, sum = 0;

            String s = Integer.toString(n); //converting the number into a String

            int len = s.length(); //finding the length of the number i.e. no.of digits

             

            while(copy>0)

            {

                d = copy % 10; //extracting the last digit

                sum = sum + (int)Math.pow(d,len);

                len--;

                copy = copy / 10;

            }

             

            if(sum == n)

                System.out.println(n+" is a Disarium Number.");

            else

                System.out.println(n+" is not a Disarium Number.");

        }

    }




Output:

Enter a Number : 135
135 is a Disarium Number.

Enter a Number : 219
219 is not a Disarium Number.

Enter a Number : 89
89 is a Disarium Number.