Java Program to check for Disarium Number

Write a Program in Java to input a number and check whether it is a Disarium Number or not.

Note: A number will be called DISARIUM if sum of its digits powered with their respective position is equal to the original number.

For example 135 is a DISARIUM
(Workings 1¹+3²+5³ = 135, some other DISARIUM are 89, 175, 518 etc)

Programming Code:

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33

/** * The class Disarium inputs a number and checks whether * it is a Disarium number or not * @author : www.javaforschool.com * @Program Type : BlueJ Program - Java */ import java.io.*; class Disarium     {     public static void main(String[] args)throws IOException         {             BufferedReader br=new BufferedReader (new InputStreamReader(System.in));             System.out.print("Enter a number : ");             int n = Integer.parseInt(br.readLine());             int copy = n, d = 0, sum = 0;             String s = Integer.toString(n); //converting the number into a String             int len = s.length(); //finding the length of the number i.e. no.of digits                           while(copy>0)             {                 d = copy % 10; //extracting the last digit                 sum = sum + (int)Math.pow(d,len);                 len--;                 copy = copy / 10;             }                           if(sum == n)                 System.out.println(n+" is a Disarium Number.");             else                 System.out.println(n+" is not a Disarium Number.");         }     }

Output:

Enter a Number : 135
135 is a Disarium Number.
Enter a Number : 219
219 is not a Disarium Number.
Enter a Number : 89
89 is a Disarium Number.