Nearest to 21

input two numbers greater than zero and print which one of them is nearest to 21 without getting over the number 21

import java.io.*;

class Nearer

    {

        public static void main(String args[])throws IOException

        {

            BufferedReader br=new BufferedReader(new InputStreamReader(System.in));

             

            System.out.print("Enter 1st number : ");

            int a = Integer.parseInt(br.readLine());

            System.out.print("Enter 2nd number : ");

            int b = Integer.parseInt(br.readLine());

             

            int d1 = Math.abs(21-a);

            int d2 = Math.abs(21-b);

             

            if(d1 > d2)

                System.out.println(b+" is nearer to 21.");

            else if(d2 > d1)

                System.out.println(a+" is nearer to 21.");

            else

                System.out.println("Both "+a+" and "+b+" are at equal distance from 21.");

        }

    }