Program on Decimal to Hexadecimal Number Conversion

Write a Program in Java to input a number in Decimal number system and convert it into its equivalent number in the Hexadecimal number system.
Note: Hexadecimal Number system is a number system which can represent a number in any other number system in terms of digits ranging from 0 to 9 and then A – F only. This number system consists of only sixteen basic digits i.e. 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E and F. Here 10 is represented as A, 11 as B and so on till 15 which is represented as F.
For Example: 47 in the Decimal number system can be represented as 2F in the Hexadecimal number system.
hexadecimal to binary

import java.io.*;
class Dec2Hex
{
    public static void main(String args[])throws IOException
    {
        BufferedReader br=new BufferedReader (new InputStreamReader(System.in));
        System.out.print("Enter a decimal number : ");
        int n=Integer.parseInt(br.readLine());
 
        int r;
        String s=""; //variable for storing the result
 
        //array storing the digits (as characters) in a hexadecimal number system
        char dig[]={'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'};
 
        while(n>0)
            {
                r=n%16; //finding remainder by dividing the number by 16
                s=dig[r]+s; //adding the remainder to the result
                n=n/16;
            }
        System.out.println("Output = "+s);
    }
}

Output:

Enter a decimal number : 47
Output = 2F
Enter a decimal number : 1243
Output = 4DB

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